Lösung 3.3:5d
Aus Online Mathematik Brückenkurs 1
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K (Lösning 3.3:5d moved to Solution 3.3:5d: Robot: moved page) |
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| - | { | + | Since |
| - | < | + | <math>e^{1}=e</math>, |
| - | + | <math>\ln e=1</math> | |
| + | and we have that | ||
| + | <math>\ln e-1=1-1=0.</math> | ||
Version vom 08:41, 26. Sep. 2008
Since \displaystyle e^{1}=e, \displaystyle \ln e=1 and we have that \displaystyle \ln e-1=1-1=0.
