Lösung 3.3:2a
Aus Online Mathematik Brückenkurs 1
(Unterschied zwischen Versionen)
K (Lösning 3.3:2a moved to Solution 3.3:2a: Robot: moved page) |
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| - | {{ | + | The logarithm |
| - | < | + | <math>\text{lg }0.\text{1 }</math> |
| - | {{ | + | is defined as that number which should stand in the (??) grey box in order that the equality |
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| + | <math>10^{??}=0.1</math> | ||
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| + | should hold. In this case, we see that | ||
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| + | <math>10^{-1}=0.1</math> | ||
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| + | and therefore | ||
| + | <math>\text{lg }0.\text{1}=-\text{1}</math>. | ||
Version vom 13:05, 25. Sep. 2008
The logarithm \displaystyle \text{lg }0.\text{1 } is defined as that number which should stand in the (??) grey box in order that the equality
\displaystyle 10^{??}=0.1
should hold. In this case, we see that
\displaystyle 10^{-1}=0.1
and therefore
\displaystyle \text{lg }0.\text{1}=-\text{1}.
