Lösung 2.2:1c
Aus Online Mathematik Brückenkurs 1
(Unterschied zwischen Versionen)
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- | Because there is an | + | Because there is an ''x'' on both the left- and right-hand sides, the first step is to subtract ''x''/3 from both sides, |
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- | on both the left- and right-hand sides, | + | |
- | + | {{Displayed math||<math>\tfrac{1}{3}x-1-\tfrac{1}{3}x=x-\tfrac{1}{3}x</math>}} | |
- | <math>{x} | + | |
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+ | so as to collect ''x'' on the right-hand side | ||
- | <math> | + | {{Displayed math||<math>-1=\tfrac{2}{3}x\,\textrm{.}</math>}} |
+ | Then, multiply both sides by 3/2, | ||
- | + | {{Displayed math||<math>\tfrac{3}{2}\cdot (-1) = \tfrac{3}{2}\cdot\tfrac{2}{3}x\,,</math>}} | |
- | <math>x</math> | + | |
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+ | so that 2/3 can be eliminated on the right-hand side to give us | ||
- | + | {{Displayed math||<math>-\tfrac{3}{2}=x\,\textrm{.}</math>}} | |
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Version vom 13:19, 23. Sep. 2008
Because there is an x on both the left- and right-hand sides, the first step is to subtract x/3 from both sides,
so as to collect x on the right-hand side
Then, multiply both sides by 3/2,
so that 2/3 can be eliminated on the right-hand side to give us