Lösung 2.1:3f
Aus Online Mathematik Brückenkurs 1
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Treating <math>4x</math> as one term, we can write | Treating <math>4x</math> as one term, we can write | ||
| - | <math> \qquad 16x^2+8x+1=(4x)^2 +2\cdot 4x +1 </math> | + | {{Displayed math||<math> \qquad 16x^2+8x+1=(4x)^2 +2\cdot 4x +1 </math>}} |
and since <math> y^2 +2y+1=(y+1)^2 </math> we obtain | and since <math> y^2 +2y+1=(y+1)^2 </math> we obtain | ||
| - | <math> \qquad (4x)^2 +2\cdot 4x +1= (4x+1)^2 </math> | + | {{Displayed math||<math> \qquad (4x)^2 +2\cdot 4x +1= (4x+1)^2 </math>.}} |
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Version vom 08:39, 23. Sep. 2008
Treating \displaystyle 4x as one term, we can write
and since \displaystyle y^2 +2y+1=(y+1)^2 we obtain
