Lösung 1.3:2a

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We can write every factor in the expression as a power of
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We can write every factor in the expression as a power of 2,
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<math>2</math>,
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<math>\begin{align}
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& 2=2^{1} \\
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& \\
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& 4=2\centerdot 2=2^{2} \\
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& \\
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& 8=2\centerdot 4=2\centerdot 2\centerdot 2=2^{3} \\
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\end{align}</math>
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{{Displayed math||<math>\begin{align}
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2 &= 2^{1}\,, \\
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4 &= 2\cdot 2 = 2^{2}\,,\\
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8 &= 2\cdot 4 = 2\cdot 2\cdot 2 = 2^{3}\,,
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\end{align}</math>}}
which gives
which gives
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{{Displayed math||<math>2\cdot 4\cdot 8 = 2^{1}\cdot 2^{2}\cdot 2^{3} = 2^{1+2+3} = 2^{6}\,</math>.}}
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<math>2\centerdot 4\centerdot 8=2^{1}\centerdot 2^{2}\centerdot 2^{3}=2^{1+2+3}=2^{6}</math>
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Version vom 12:53, 22. Sep. 2008

We can write every factor in the expression as a power of 2,

Vorlage:Displayed math

which gives

Vorlage:Displayed math

Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_1.3:2a“