Lösung 1.2:6
Aus Online Mathematik Brückenkurs 1
(Unterschied zwischen Versionen)
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the answer can be simplified to | the answer can be simplified to | ||
| - | {{Displayed math||<math>\frac{38\cdot 12}{15\cdot 7}=\frac{2\cdot 19\cdot 2\cdot 2\cdot{}\rlap{/}3}{\rlap{/}3\cdot 5\cdot 7}=\frac{ | + | {{Displayed math||<math>\frac{38\cdot 12}{15\cdot 7}=\frac{2\cdot 19\cdot 2\cdot 2\cdot{}\rlap{/}3}{\rlap{/}3\cdot 5\cdot 7}=\frac{152}{35}\,</math>.}} |
Version vom 12:35, 22. Sep. 2008
When we work with large expressions, it is often best to proceed step by step. A first step on the way can be to simplify all the parts
We can do this by multiplying the top and bottom of each fraction by 2, 12 and 7 respectively, so as to get rid of the partial fractions
The whole expression therefore equals
If we multiply the tops and bottoms of the fractions 4/7, 1/2 and 21/12 in the main fraction by their lowest common denominator, \displaystyle 7\cdot 12, we obtain integers in the numerator and denominator
By factorizing 12, 15 and 38,
the answer can be simplified to
