Lösung 3.1:1d

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Because
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<center> [[Image:3_1_1d.gif]] </center>
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<math>\sqrt{3}</math>
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is
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<math>3^{\frac{1}{2}}</math>, then
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<math>\sqrt{\sqrt{3}}=\sqrt{3^{{1}/{2}\;}}=\left( 3^{{1}/{2}\;} \right)^{{1}/{2}\;}=3^{\frac{1}{2}\centerdot \frac{1}{2}}=3^{{1}/{4}\;}</math>

Version vom 10:17, 22. Sep. 2008

Because \displaystyle \sqrt{3} is \displaystyle 3^{\frac{1}{2}}, then \displaystyle \sqrt{\sqrt{3}}=\sqrt{3^{{1}/{2}\;}}=\left( 3^{{1}/{2}\;} \right)^{{1}/{2}\;}=3^{\frac{1}{2}\centerdot \frac{1}{2}}=3^{{1}/{4}\;}

Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_3.1:1d“