Lösung 2.2:8c

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By moving the term in
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<math>x</math>
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over to the right-hand side and dividing by
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<math>3</math>, the inequality can be rewritten as
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<math>y\le 2-\frac{2}{3}x</math>.
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Then, we see that the area that we should shade consists of all the points under the straight line
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<math>y=2-\frac{2}{3}x</math>.
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<center> [[Image:2_2_8c.gif]] </center>
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[[Image:2_2_8_c.gif|center]]
[[Image:2_2_8_c.gif|center]]

Version vom 12:40, 18. Sep. 2008

By moving the term in \displaystyle x over to the right-hand side and dividing by \displaystyle 3, the inequality can be rewritten as


\displaystyle y\le 2-\frac{2}{3}x.

Then, we see that the area that we should shade consists of all the points under the straight line

\displaystyle y=2-\frac{2}{3}x.


Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_2.2:8c“