Lösung 2.2:6a
Aus Online Mathematik Brückenkurs 1
(Unterschied zwischen Versionen)
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+ | According to the definition, the point of intersection between two lines is that point which lies on both lines; it must therefore satisfy the equations of both lines. | ||
+ | |||
+ | If the point of intersection has coordinates | ||
+ | <math>\left( x \right.,\left. y \right)</math>, then | ||
+ | |||
+ | <math>y=3x+5</math> | ||
+ | |||
+ | and | ||
+ | |||
+ | <math>y=0</math> | ||
+ | ( | ||
+ | <math>x</math> | ||
+ | -axis) | ||
+ | |||
+ | If we substitute | ||
+ | <math>y=0</math> | ||
+ | into the first equation, we obtain | ||
+ | |||
+ | |||
+ | <math>0=3x+5</math> | ||
+ | i.e. | ||
+ | <math>x=-\frac{5}{3}</math> | ||
+ | |||
+ | |||
+ | The point of intersection is | ||
+ | <math>\left( -\frac{5}{3} \right.,\left. 0 \right)</math>. | ||
+ | |||
+ | |||
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Version vom 10:16, 18. Sep. 2008
According to the definition, the point of intersection between two lines is that point which lies on both lines; it must therefore satisfy the equations of both lines.
If the point of intersection has coordinates \displaystyle \left( x \right.,\left. y \right), then
\displaystyle y=3x+5
and
\displaystyle y=0 ( \displaystyle x -axis)
If we substitute \displaystyle y=0 into the first equation, we obtain
\displaystyle 0=3x+5
i.e.
\displaystyle x=-\frac{5}{3}
The point of intersection is
\displaystyle \left( -\frac{5}{3} \right.,\left. 0 \right).