Lösung 1.3:1a

Aus Online Mathematik Brückenkurs 1

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{{NAVCONTENT_START}}
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We calculate
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<center> [[Image:1_3_1a.gif]] </center>
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<math>2^{3}</math>
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first and then
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<math>3^{2}</math>
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<math>\begin{align}
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& 2^{3}=2\centerdot 2\centerdot 2=4\centerdot 2=8, \\
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& \\
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& 3^{2}=3\centerdot 3=9 \\
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\end{align}</math>
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Hence,
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<math>2^{3}\centerdot 3^{2}=8\centerdot 9=72</math>

Version vom 11:00, 15. Sep. 2008

We calculate \displaystyle 2^{3} first and then \displaystyle 3^{2}


\displaystyle \begin{align} & 2^{3}=2\centerdot 2\centerdot 2=4\centerdot 2=8, \\ & \\ & 3^{2}=3\centerdot 3=9 \\ \end{align}


Hence,


\displaystyle 2^{3}\centerdot 3^{2}=8\centerdot 9=72

Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_1.3:1a“