Lösung 1.1:2c
Aus Online Mathematik Brückenkurs 1
(Unterschied zwischen Versionen)
K (Lösning 1.1:2c moved to Solution 1.1:2c: Robot: moved page) |
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| - | + | We can divide up the whole expression into two separate parts | |
<center><math>\bbox[#FFEEAA;,1.5pt]{\,3\cdot(-7)\,}-\bbox[#FFEEAA;,1.5pt]{\,4\cdot(6-5)\,}</math></center> | <center><math>\bbox[#FFEEAA;,1.5pt]{\,3\cdot(-7)\,}-\bbox[#FFEEAA;,1.5pt]{\,4\cdot(6-5)\,}</math></center> | ||
| - | + | which we first calculate and then combine. | |
{{NAVCONTENT_STEP}} | {{NAVCONTENT_STEP}} | ||
| - | + | The first part of the expression equals | |
<center><math>3\cdot(-7) = -21</math></center> | <center><math>3\cdot(-7) = -21</math></center> | ||
{{NAVCONTENT_STEP}} | {{NAVCONTENT_STEP}} | ||
| - | + | whilst the second expression becomes. | |
<center><math>4\cdot(6-5) = 4\cdot 1 = 4\,</math>.</center> | <center><math>4\cdot(6-5) = 4\cdot 1 = 4\,</math>.</center> | ||
{{NAVCONTENT_STEP}} | {{NAVCONTENT_STEP}} | ||
| - | + | Combining, we obtain | |
<center><math>\bbox[#FFEEAA;,1.5pt]{\,3\cdot(-7)\,}-\bbox[#FFEEAA;,1.5pt]{\,4\cdot(6-5)\,} = \bbox[#FFEEAA;,1.5pt]{\,-21\,}-\bbox[#FFEEAA;,1.5pt]{\,4\,} = -25\,</math>.</center> | <center><math>\bbox[#FFEEAA;,1.5pt]{\,3\cdot(-7)\,}-\bbox[#FFEEAA;,1.5pt]{\,4\cdot(6-5)\,} = \bbox[#FFEEAA;,1.5pt]{\,-21\,}-\bbox[#FFEEAA;,1.5pt]{\,4\,} = -25\,</math>.</center> | ||
{{NAVCONTENT_STOP}} | {{NAVCONTENT_STOP}} | ||
<!--<center> [[Image:1_1_2c.gif]] </center> --> | <!--<center> [[Image:1_1_2c.gif]] </center> --> | ||
Version vom 13:13, 13. Sep. 2008
We can divide up the whole expression into two separate parts
which we first calculate and then combine.
The first part of the expression equals
whilst the second expression becomes.
Combining, we obtain
