Antwort 4.3:5

Aus Online Mathematik Brückenkurs 1

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||<math>\cos{v}=\displaystyle \frac{2\sqrt{6}}{7}\quad</math> och <math>\quad\tan{v}=\displaystyle \frac{5}{2\sqrt{6}}\,</math>.
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||<math>\cos{v}=\displaystyle \frac{2\sqrt{6}}{7}\quad</math> and <math>\quad\tan{v}=\displaystyle \frac{5}{2\sqrt{6}}\,</math>.
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Version vom 11:00, 8. Sep. 2008

\displaystyle \cos{v}=\displaystyle \frac{2\sqrt{6}}{7}\quad and \displaystyle \quad\tan{v}=\displaystyle \frac{5}{2\sqrt{6}}\,.
Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/Antwort_4.3:5“