Lösung 2.1:3b
Aus Online Mathematik Brückenkurs 1
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| - | <center> [[Bild:2_1_3b.gif]] </center> | + | If we take out the factor 5, we see that the expression can be factorized using the conjugate rule |
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| + | <math> \qquad \begin{align} | ||
| + | 5x^2-20&=5(x^4-4)\\ | ||
| + | &= 5(x^2-2^2)\\ | ||
| + | &= 5(x+2)(x-2) | ||
| + | \end{align} | ||
| + | </math> | ||
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Version vom 13:03, 13. Aug. 2008
If we take out the factor 5, we see that the expression can be factorized using the conjugate rule
\displaystyle \qquad \begin{align} 5x^2-20&=5(x^4-4)\\ &= 5(x^2-2^2)\\ &= 5(x+2)(x-2) \end{align}
