Antwort 3.1:8

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K (Svar 3.1:8 moved to Answer 3.1:8: Robot: moved page)

Version vom 14:43, 8. Sep. 2008

a) \displaystyle \sqrt[\scriptstyle3]6 > \sqrt[\scriptstyle3]5 b) \displaystyle 7 > \sqrt7
c) \displaystyle \sqrt7 > 2{,}5 d) \displaystyle \sqrt[\scriptstyle3]2\cdot3 > \sqrt2\bigl(\sqrt[\scriptstyle4]3\,\bigr)^3