Antwort 2.3:3
Aus Online Mathematik Brückenkurs 1
(Unterschied zwischen Versionen)
(Ny sida: {| width="100%" cellspacing="10px" |a) |width="50%" | <math>\left\{ \eqalign{ x_1 &= 0 \cr x_2 & = -3\cr }\right.</math> |b) |width="50%" | <math>\left\{ \eqalign{ x_1 &= 3 \cr x_2 & = -5\...) |
K (Svar 2.3:3 moved to Answer 2.3:3: Robot: moved page) |
Version vom 14:38, 8. Sep. 2008
| a) | \displaystyle \left\{ \eqalign{ x_1 &= 0 \cr x_2 & = -3\cr }\right. | b) | \displaystyle \left\{ \eqalign{ x_1 &= 3 \cr x_2 & = -5\cr }\right. |
| c) | \displaystyle \left\{ \eqalign{ x_1 & = \textstyle\frac{2}{3} \cr x_2 & = -8\cr }\right. | d) | \displaystyle \left\{ \eqalign{ x_1 & = 0\cr x_2 & = 12\cr }\right. |
| e) | \displaystyle \left\{ \eqalign{ x_1 & = -3 \cr x_2 & = 8\cr }\right. | f) | \displaystyle \left\{ \eqalign{ x_1 & = 0 \cr x_2 & = 1 \cr x_3 & = 2 }\right. |
