3.4 Übungen
Aus Online Mathematik Brückenkurs 1
(Unterschied zwischen Versionen)
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</div>{{#NAVCONTENT:Answer|Answer 3.4:1|Solution a|Solution 3.4:1a|Solution b|Solution 3.4:1b|Solution c|Solution 3.4:1c}} | </div>{{#NAVCONTENT:Answer|Answer 3.4:1|Solution a|Solution 3.4:1a|Solution b|Solution 3.4:1b|Solution c|Solution 3.4:1c}} | ||
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</div>{{#NAVCONTENT:Answer|Answer 3.4:2|Solution a|Solution 3.4:2a|Solution b|Solution 3.4:2b|Solution c|Solution 3.4:2c}} | </div>{{#NAVCONTENT:Answer|Answer 3.4:2|Solution a|Solution 3.4:2a|Solution b|Solution 3.4:2b|Solution c|Solution 3.4:2c}} | ||
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Version vom 09:15, 22. Okt. 2008
Übung 3.4:1
Solve the equation
| a) | \displaystyle e^x=13 | b) | \displaystyle 13e^x=2\cdot3^{-x} | c) | \displaystyle 3e^x=7\cdot2^x |
Answer
Laden...
Solution a
Solution b
Solution c
Übung 3.4:2
Solve the equation
| a) | \displaystyle 2^{\scriptstyle x^2-2}=1 | b) | \displaystyle e^{2x}+e^x=4 | c) | \displaystyle 3e^{x^2}=2^x |
Answer
Solution a
Solution b
Solution c
Übung 3.4:3
Solve the equation
| a) | \displaystyle 2^{-x^2}=2e^{2x} | b) | \displaystyle \ln{(x^2+3x)}=\ln{(3x^2-2x)} |
| c) | \displaystyle \ln{x}+\ln{(x+4)}=\ln{(2x+3)} |
Answer
Solution a
Solution b
Solution c
