1.2 Übungen

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===Exercise 1.2:1===
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===Übung 1.2:1===
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Write as one fraction
Write as one fraction
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===Exercise 1.2:2===
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===Übung 1.2:2===
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Determine the lowest common denominator of
Determine the lowest common denominator of
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===Exercise 1.2:3===
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===Übung 1.2:3===
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Calculate the following by using the lowest common denominator.
Calculate the following by using the lowest common denominator.
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===Exercise 1.2:4===
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===Übung 1.2:4===
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Simplify the following by writing each part as one fraction. The fraction should be in simplest possible form.
Simplify the following by writing each part as one fraction. The fraction should be in simplest possible form.
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===Exercise 1.2:5===
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===Übung 1.2:5===
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Simplify the following by writing each part as one fraction. The fraction should be in simplest possible form.
Simplify the following by writing each part as one fraction. The fraction should be in simplest possible form.
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===Exercise 1.2:6===
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===Übung 1.2:6===
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Simplify
Simplify
<math>\ \,\displaystyle \frac{\displaystyle \frac{2}{\displaystyle 3+\frac{1}{2}}\displaystyle + \frac{\displaystyle \frac{1}{2}}{\displaystyle \frac{1}{4}\displaystyle -\frac{1}{3}}}{\displaystyle \frac{1}{2}\displaystyle - \frac{3}{\displaystyle 2-\frac{2}{7}}}</math>
<math>\ \,\displaystyle \frac{\displaystyle \frac{2}{\displaystyle 3+\frac{1}{2}}\displaystyle + \frac{\displaystyle \frac{1}{2}}{\displaystyle \frac{1}{4}\displaystyle -\frac{1}{3}}}{\displaystyle \frac{1}{2}\displaystyle - \frac{3}{\displaystyle 2-\frac{2}{7}}}</math>
</div>{{#NAVCONTENT:Answer|Answer 1.2:6|Solution |Solution 1.2:6}}
</div>{{#NAVCONTENT:Answer|Answer 1.2:6|Solution |Solution 1.2:6}}

Version vom 09:13, 22. Okt. 2008

 

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Übung 1.2:1

Write as one fraction

a) \displaystyle \displaystyle \frac{7}{4}+\frac{11}{7} b) \displaystyle \displaystyle \frac{2}{7}-\frac{1}{5} c) \displaystyle \displaystyle \frac{1}{6}-\frac{2}{5}
d) \displaystyle \displaystyle \frac{1}{3}+\frac{1}{4}+\frac{1}{5} e) \displaystyle \displaystyle \frac{8}{7}+\frac{3}{4}-\frac{4}{3}
Answer
Answer 1.2:1
Solution a
Solution 1.2:1a
Solution b
Solution 1.2:1b
Solution c
Solution 1.2:1c
Solution d
Solution 1.2:1d
Solution e
Solution 1.2:1e


Übung 1.2:2

Determine the lowest common denominator of

a) \displaystyle \displaystyle \frac{1}{6}+\frac{1}{10} b) \displaystyle \displaystyle \frac{1}{4}-\frac{1}{8}
c) \displaystyle \displaystyle \frac{1}{12}-\frac{1}{14} d) \displaystyle \displaystyle \frac{2}{45}+\frac{1}{75}
Answer
Answer 1.2:2
Solution a
Solution 1.2:2a
Solution b
Solution 1.2:2b
Solution c
Solution 1.2:2c
Solution d
Solution 1.2:2d


Übung 1.2:3

Calculate the following by using the lowest common denominator.

a) \displaystyle \displaystyle\frac{3}{20}+\frac{7}{50}-\frac{1}{10} b) \displaystyle \displaystyle\frac{1}{24}+\frac{1}{40}-\frac{1}{16}
Answer
Answer 1.2:3
Solution a
Solution 1.2:3a
Solution b
Solution 1.2:3b


Übung 1.2:4

Simplify the following by writing each part as one fraction. The fraction should be in simplest possible form.

a) \displaystyle \displaystyle\frac{\displaystyle\frac{3}{5}}{\displaystyle\frac{7}{10}} b) \displaystyle \displaystyle\frac{\displaystyle\frac{2}{7}}{\displaystyle\frac{3}{8}} c) \displaystyle \displaystyle\frac{\displaystyle\frac{1}{4}-\frac{1}{5}}{\displaystyle\frac{3}{10}}
Answer
Answer 1.2:4
Solution a
Solution 1.2:4a
Solution b
Solution 1.2:4b
Solution c
Solution 1.2:4c


Übung 1.2:5

Simplify the following by writing each part as one fraction. The fraction should be in simplest possible form.

a) \displaystyle \displaystyle \frac{2}{\displaystyle \frac{1}{7}\displaystyle -\frac{1}{15}} b) \displaystyle \displaystyle\frac{\displaystyle\frac{1}{2}\displaystyle+\frac{1}{3}}{\displaystyle\frac{1}{3}\displaystyle-\frac{1}{2}} c) \displaystyle \displaystyle\frac{\displaystyle\frac{3}{10}\displaystyle-\frac{1}{5}}{\displaystyle\frac{7}{8}\displaystyle-\frac{3}{16}}
Answer
Answer 1.2:5
Solution a
Solution 1.2:5a
Solution b
Solution 1.2:5b
Solution c
Solution 1.2:5c


Übung 1.2:6

Simplify \displaystyle \ \,\displaystyle \frac{\displaystyle \frac{2}{\displaystyle 3+\frac{1}{2}}\displaystyle + \frac{\displaystyle \frac{1}{2}}{\displaystyle \frac{1}{4}\displaystyle -\frac{1}{3}}}{\displaystyle \frac{1}{2}\displaystyle - \frac{3}{\displaystyle 2-\frac{2}{7}}}

Answer
Answer 1.2:6
Solution
Solution 1.2:6
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