Lösung 4.2:2b
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Version vom 14:52, 22. Okt. 2008
In this right-angled triangle, the opposite and the hypotenuse are given. This means that we can directly set up a relation for the sine of the angle v,
| \displaystyle \sin v = \frac{70}{110}\,\textrm{.} | 
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The right-hand side in this equation can be simplified, so that we get
| \displaystyle \sin v = \frac{7}{11}\,\textrm{.} |
