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Lösung 3.1:3c

Aus Online Mathematik Brückenkurs 1

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Version vom 14:20, 22. Okt. 2008

We start by looking at one part of the expression 16 . This subexpression can be simplified since 16=44=42 which gives that 16=42=4  and the whole expression becomes

16+16=16+4=20. 

Can 20  be simplified? In order to answer this, we split 20 up into integer factors,

20=210=225=225

and see that 20 contains the square 22 as a factor and can therefore be taken outside the root sign,

20=225=25. 
Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_3.1:3c“