Lösung 4.4:3c
Aus Online Mathematik Brückenkurs 1
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- | If we consider the entire expression | + | If we consider the entire expression <math>x + 40^{\circ}</math> as an unknown, we have a basic trigonometric equation and can, with the aid of the unit circle, see that there are two solutions to the equation for <math>0^{\circ}\le x+40^{\circ}\le 360^{\circ}</math> namely <math>x+40^{\circ} = 65^{\circ}</math> and the symmetric solution <math>x + 40^{\circ} = 180^{\circ} - 65^{\circ} = 115^{\circ}\,</math>. |
- | <math>x+ | + | |
- | as an unknown, we have a | + | |
- | <math>0^{\circ }\le x+ | + | |
- | namely | + | |
- | <math>x+ | + | |
- | and the symmetric solution | + | |
- | <math>x+ | + | |
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[[Image:4_4_3_c.gif|center]] | [[Image:4_4_3_c.gif|center]] | ||
- | It is then easy to set up the general solution by adding multiples of | + | It is then easy to set up the general solution by adding multiples of <math>360^{\circ}\,</math>, |
- | <math>360^{\circ }</math>, | + | |
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- | + | {{Displayed math||<math>x + 40^{\circ} = 65^{\circ} + n\cdot 360^{\circ}\qquad\text{and}\qquad x + 40^{\circ} = 115^{\circ} + n\cdot 360^{\circ}</math>}} | |
- | <math>n</math> | + | |
+ | for all integers ''n'', which gives | ||
- | <math>x= | + | {{Displayed math||<math>x = 25^{\circ} + n\cdot 360^{\circ}\qquad\text{and}\qquad x=75^{\circ} + n\cdot 360^{\circ}\,\textrm{.}</math>}} |
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Version vom 12:58, 13. Okt. 2008
If we consider the entire expression \displaystyle x + 40^{\circ} as an unknown, we have a basic trigonometric equation and can, with the aid of the unit circle, see that there are two solutions to the equation for \displaystyle 0^{\circ}\le x+40^{\circ}\le 360^{\circ} namely \displaystyle x+40^{\circ} = 65^{\circ} and the symmetric solution \displaystyle x + 40^{\circ} = 180^{\circ} - 65^{\circ} = 115^{\circ}\,.
It is then easy to set up the general solution by adding multiples of \displaystyle 360^{\circ}\,,
for all integers n, which gives