Lösung 4.3:2a

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On a unit circle, the angle
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On the unit circle, the angle <math>3\pi/2</math> corresponds to the point (0,-1), and the angle in the interval from <math>0</math> to <math>\pi</math> which has the same cosine value as <math>3\pi/2</math>, i.e. the ''x''-coordinate <math>0</math>, is the angle <math>v = \pi/2\,</math>.
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<math>{3\pi }/{2}\;</math>
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corresponds to the point
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<math>\left( 0 \right.,\left. -1 \right)</math>, and the angle in the interval from
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<math>0</math>
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to
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<math>\pi </math>
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which has the same cosine value as
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<math>{3\pi }/{2}\;</math>, i.e. the x-coordinate
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<math>0</math>, is the angle
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<math>v={\pi }/{2}\;</math>.
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[[Image:4_3_2_a.gif||center]]
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<center> [[Image:4_3_2_a.gif]] </center>
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Version vom 13:09, 9. Okt. 2008

On the unit circle, the angle \displaystyle 3\pi/2 corresponds to the point (0,-1), and the angle in the interval from \displaystyle 0 to \displaystyle \pi which has the same cosine value as \displaystyle 3\pi/2, i.e. the x-coordinate \displaystyle 0, is the angle \displaystyle v = \pi/2\,.

Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_4.3:2a“