Lösung 4.1:8

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Because the wheel's circumference is
Because the wheel's circumference is
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{{Displayed math||<math>2\pi\cdot\text{(radius)} = 2\pi\cdot 0\textrm{.}5\ \text{metres} = \pi\ \text{metres}</math>}}
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<math>2\pi \centerdot </math>
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the wheel turns <math>\pi</math> metres on each revolution, and in 10 metres the wheel therefore turns
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radius metres metres
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the wheel turns
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{{Displayed math||<math>\frac{10\ \text{metres}}{\pi\ \text{metres}} = \frac{10}{\pi }\ \textrm{revolutions}\approx 3\textrm{.}2\ \textrm{revolutions.}</math>}}
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<math>\pi </math>
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metres on each revolution, and in
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<math>\text{1}0</math>
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metres the wheel therefore turns
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<math>\frac{10\ \text{metres}}{\pi \ \text{metres}}=\frac{10}{\pi }\approx 3.2</math>
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revolutions
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Version vom 11:46, 8. Okt. 2008

Because the wheel's circumference is

Vorlage:Displayed math

the wheel turns \displaystyle \pi metres on each revolution, and in 10 metres the wheel therefore turns

Vorlage:Displayed math

Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_4.1:8“