Lösung 4.1:6b
Aus Online Mathematik Brückenkurs 1
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| - | A quick way to interpret the equation is to compare it with the standard formula for the equation of a circle with centre at | + | A quick way to interpret the equation is to compare it with the standard formula for the equation of a circle with centre at (''a'',''b'') and radius ''r'', |
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| - | and radius | + | |
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| + | {{Displayed math||<math>(x-a)^2 + (y-b)^2 = r^2\,\textrm{.}</math>}} | ||
In our case, we can write the equation as | In our case, we can write the equation as | ||
| + | {{Displayed math||<math>(x-1)^2 + (y-2)^2 = (\sqrt{3})^2</math>}} | ||
| - | + | and then we see that it describes a circle with centre at (1,2) and radius <math>\sqrt{3}\,</math>. | |
| - | and then we see that it describes a circle with centre at | ||
| - | <math>\left( 1 \right.,\left. 2 \right)</math> | ||
| - | and radius | ||
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| - | {{NAVCONTENT_START}} | ||
[[Image:4_1_6_b.gif|center]] | [[Image:4_1_6_b.gif|center]] | ||
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| - | {{NAVCONTENT_STOP}} | ||
Version vom 10:36, 8. Okt. 2008
A quick way to interpret the equation is to compare it with the standard formula for the equation of a circle with centre at (a,b) and radius r,
In our case, we can write the equation as
and then we see that it describes a circle with centre at (1,2) and radius \displaystyle \sqrt{3}\,.

