Lösung 2.2:6b
Aus Online Mathematik Brückenkurs 1
(Unterschied zwischen Versionen)
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Because the point of intersection lies on both lines, it must satisfy the equations of both lines | Because the point of intersection lies on both lines, it must satisfy the equations of both lines | ||
| - | {{ | + | {{Abgesetzte Formel||<math>y=-x+5\qquad\text{and}\qquad x=0\,,</math>}} |
where <math>x=0</math> is the equation of the ''y''-axis. Substituting the second equation, <math>x=0</math>, into the first equation gives <math>y=-0+5=5</math>. This means that the point of intersection is (0,5). | where <math>x=0</math> is the equation of the ''y''-axis. Substituting the second equation, <math>x=0</math>, into the first equation gives <math>y=-0+5=5</math>. This means that the point of intersection is (0,5). | ||
Version vom 08:29, 22. Okt. 2008
Because the point of intersection lies on both lines, it must satisfy the equations of both lines
| \displaystyle y=-x+5\qquad\text{and}\qquad x=0\,, |
where \displaystyle x=0 is the equation of the y-axis. Substituting the second equation, \displaystyle x=0, into the first equation gives \displaystyle y=-0+5=5. This means that the point of intersection is (0,5).
