Lösung 2.2:4b

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By taking <math>4y</math> out of the relation <math>3x+4y-5=0</math>, we get
By taking <math>4y</math> out of the relation <math>3x+4y-5=0</math>, we get
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{{Displayed math||<math>4y=-3x+5\,\textrm{.}</math>}}
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{{Abgesetzte Formel||<math>4y=-3x+5\,\textrm{.}</math>}}
Dividing by 4 then gives the answer in the desired form
Dividing by 4 then gives the answer in the desired form
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{{Displayed math||<math>y=-\frac{3}{4}x+\frac{5}{4}\,\textrm{.}</math>}}
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{{Abgesetzte Formel||<math>y=-\frac{3}{4}x+\frac{5}{4}\,\textrm{.}</math>}}

Version vom 08:28, 22. Okt. 2008

By taking \displaystyle 4y out of the relation \displaystyle 3x+4y-5=0, we get

\displaystyle 4y=-3x+5\,\textrm{.}

Dividing by 4 then gives the answer in the desired form

\displaystyle y=-\frac{3}{4}x+\frac{5}{4}\,\textrm{.}
Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_2.2:4b“