Lösung 2.1:3f
Aus Online Mathematik Brückenkurs 1
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| - | <center> [[Bild:2_1_3f.gif]] </center> | + | Treating <math>4x</math> as one term, we can write |
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| + | <math> \qquad 16x^2+8x+1=(4x)^2 +2\cdot 4x +1 </math> | ||
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| + | and because <math> y^2 +2y+1=(y+1)^2 </math> we obtain | ||
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| + | <math> \qquad (4x)^2 +2\cdot 4x +1= (4x+1)^2 </math> | ||
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Version vom 13:23, 13. Aug. 2008
Treating \displaystyle 4x as one term, we can write
\displaystyle \qquad 16x^2+8x+1=(4x)^2 +2\cdot 4x +1
and because \displaystyle y^2 +2y+1=(y+1)^2 we obtain
\displaystyle \qquad (4x)^2 +2\cdot 4x +1= (4x+1)^2
