Lösung 1.2:1b

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Subtraction works in the same way as addition. First, we multiply the top and bottom of each fraction by the other fraction's denominator so that they have a common denominator,
Subtraction works in the same way as addition. First, we multiply the top and bottom of each fraction by the other fraction's denominator so that they have a common denominator,
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{{Displayed math||<math>\frac{2\cdot 5}{7\cdot 5}-\frac{1\cdot 7}{5\cdot 7}=\frac{10}{35}-\frac{7}{35}\,</math>.}}
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{{Abgesetzte Formel||<math>\frac{2\cdot 5}{7\cdot 5}-\frac{1\cdot 7}{5\cdot 7}=\frac{10}{35}-\frac{7}{35}\,</math>.}}
Then the numerators can be subtracted,
Then the numerators can be subtracted,
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{{Displayed math||<math>\frac{10}{35}-\frac{7}{35}=\frac{10-7}{35}=\frac{3}{35}\,</math>.}}
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{{Abgesetzte Formel||<math>\frac{10}{35}-\frac{7}{35}=\frac{10-7}{35}=\frac{3}{35}\,</math>.}}

Version vom 08:13, 22. Okt. 2008

Subtraction works in the same way as addition. First, we multiply the top and bottom of each fraction by the other fraction's denominator so that they have a common denominator,

\displaystyle \frac{2\cdot 5}{7\cdot 5}-\frac{1\cdot 7}{5\cdot 7}=\frac{10}{35}-\frac{7}{35}\,.

Then the numerators can be subtracted,

\displaystyle \frac{10}{35}-\frac{7}{35}=\frac{10-7}{35}=\frac{3}{35}\,.
Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_1.2:1b“