Lösung 2.2:1b

Aus Online Mathematik Brückenkurs 1

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To get
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To get ''x'' by itself on the left-hand side, we subtract 1 from both sides
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<math>x</math>
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by itself on the left-hand side, we subtract
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<math>1</math>
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from both sides
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<math>2x+1-1=13-1</math>
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{{Displayed math||<math>2x+1-1=13-1</math>}}
which gives
which gives
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{{Displayed math||<math>2x=12\,\textrm{.}</math>}}
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<math>2x=12</math>
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Then divide both sides by 2,
Then divide both sides by 2,
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{{Displayed math||<math>\frac{2x}{2}=\frac{12}{2}</math>}}
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<math>\frac{2x}{2}=\frac{12}{2}</math>
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to get ''x'',
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to get
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<math>x</math>:
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<math>x=6</math>
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{{Displayed math||<math>x=6\,\textrm{.}</math>}}

Version vom 13:12, 23. Sep. 2008

To get x by itself on the left-hand side, we subtract 1 from both sides

Vorlage:Displayed math

which gives

Vorlage:Displayed math

Then divide both sides by 2,

Vorlage:Displayed math

to get x,

Vorlage:Displayed math

Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_2.2:1b“