Lösung 2.1:8c
Aus Online Mathematik Brückenkurs 1
(Unterschied zwischen Versionen)
			  			                                                      
		          
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| - | When we come across large and complicated expressions, we have to work step by step;  | + | When we come across large and complicated expressions, we have to work step by step; as a first goal, we can multiply the top and bottom of  the fraction | 
| - | + | {{Displayed math||<math>\frac{1}{1+\dfrac{1}{1+x}}</math>}} | |
| + | by <math>1+x</math>, so as to reduce it to an expression having one fraction sign | ||
| - | + | {{Displayed math||<math>\begin{align} | |
| - | + | \frac{1}{1+\dfrac{1}{1+\dfrac{1}{1+x}}} | |
| - | + | &= \frac{1}{1+\dfrac{1}{1+\dfrac{1}{1+x}}\cdot\dfrac{1+x}{1+x}}\\[8pt] | |
| - | + | &= \frac{1}{1+\dfrac{1+x}{\Bigl(1+\dfrac{1}{1+x}\Bigr)(1+x)}}\\[8pt]  | |
| - | + | &= \frac{1}{1+\dfrac{1+x}{1+x+\dfrac{1+x}{1+x}}}\\[8pt] | |
| - | + | &= \frac{1}{1+\dfrac{1+x}{1+x+1}}\\[8pt] | |
| - | + | &= \frac{1}{1+\dfrac{x+1}{x+2}}\,\textrm{.}  | |
| - | <math>\begin{align} | + | \end{align}</math>}} | 
| - | + | ||
| - | + | ||
| - | & =\frac{1}{1+\ | + | |
| - | \end{align}</math> | + | |
| - | + | ||
| The next step is to multiply the top and bottom of our new expression by  | The next step is to multiply the top and bottom of our new expression by  | ||
| - | <math>x+2</math>,  | + | <math>x+2</math>, so as to obtain the final answer, | 
| - | so as to obtain the final answer, | + | |
| - | + | ||
| - | <math>\begin{align} | + | {{Displayed math||<math>\begin{align} | 
| - | + | \frac{1}{1+\dfrac{x+1}{x+2}}\cdot\frac{x+2}{x+2} | |
| - | &  | + | &= \frac{x+2}{\Bigl(1+\dfrac{x+1}{x+2}\Bigr)(x+2)}\\[8pt] | 
| - | + | &= \frac{x+2}{x+2+\dfrac{x+1}{x+2}(x+2)}\\[8pt]  | |
| - | + | &= \frac{x+2}{x+2+x+1}\\[8pt] | |
| - | \end{align}</math> | + | &= \frac{x+2}{2x+3}\,\textrm{.} | 
| + | \end{align}</math>}} | ||
Version vom 12:41, 23. Sep. 2008
When we come across large and complicated expressions, we have to work step by step; as a first goal, we can multiply the top and bottom of the fraction
by \displaystyle 1+x, so as to reduce it to an expression having one fraction sign
The next step is to multiply the top and bottom of our new expression by \displaystyle x+2, so as to obtain the final answer,
 
		  