Lösung 1.3:3c

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The number
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The number 9 can be written as <math>\,9 = 3\cdot 3 = 3^{2}</math> and therefore
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<math>9</math>
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<math>9^{2} = (3^{2})^{2} = 3^{2\cdot 2} = 3^{4}\,</math>.
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can be written as
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<math>9=3\centerdot 3=3^{2}</math>
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and therefore
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<math>9^{2}=\left( 3^{2} \right)^{2}=3^{2\centerdot 2}=3^{4}</math>
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Version vom 13:10, 22. Sep. 2008

The number 9 can be written as \displaystyle \,9 = 3\cdot 3 = 3^{2} and therefore \displaystyle 9^{2} = (3^{2})^{2} = 3^{2\cdot 2} = 3^{4}\,.

Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_1.3:3c“