Lösung 1.2:1e
Aus Online Mathematik Brückenkurs 1
(Unterschied zwischen Versionen)
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The first step is to expand the fractions so that they have a common denominator, | The first step is to expand the fractions so that they have a common denominator, | ||
| - | + | {{Displayed math||<math>\frac{8\cdot 4\cdot 3}{7\cdot 4\cdot 3}+\frac{3\cdot 7\cdot 3}{4\cdot 7\cdot 3}-\frac{4\cdot 7\cdot 4}{3\cdot 7\cdot 4}=\frac{96}{84}+\frac{63}{84}-\frac{112}{84}\,</math>.}} | |
| - | <math>\frac{8\ | + | |
After that, the expression can be calculated by adding and subtracting the numerators | After that, the expression can be calculated by adding and subtracting the numerators | ||
| - | + | {{Displayed math||<math>\frac{96}{84}+\frac{63}{84}-\frac{112}{84}=\frac{96+63-112}{84}=\frac{47}{84}\,</math>.}} | |
| - | <math>\frac{96}{84}+\frac{63}{84}-\frac{112}{84}=\frac{96+63-112}{84}=\frac{47}{84}</math> | + | |
Version vom 07:38, 19. Sep. 2008
The first step is to expand the fractions so that they have a common denominator,
After that, the expression can be calculated by adding and subtracting the numerators
