Lösung 1.2:1c

Aus Online Mathematik Brückenkurs 1

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We multiply the top and bottom of each fraction by the other fraction's denominator so that they have a common denominator,
We multiply the top and bottom of each fraction by the other fraction's denominator so that they have a common denominator,
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{{Displayed math||<math>\frac{1}{6}-\frac{2}{5}=\frac{1\cdot 5}{6\cdot 5}-\frac{2\cdot 6}{5\cdot 6}=\frac{5}{30}-\frac{12}{30}\,</math>.}}
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<math>\frac{1}{6}-\frac{2}{5}=\frac{1\centerdot 5}{6\centerdot 5}-\frac{2\centerdot 6}{5\centerdot 6}=\frac{5}{30}-\frac{12}{30}</math>
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Then the numerators can be subtracted
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{{Displayed math||<math>\frac{5}{30}-\frac{12}{30}=\frac{5-12}{30}=\frac{-7}{30}=-\frac{7}{30}\,</math>.}}
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Then the numerators can be subtracted:
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<math>\frac{5}{30}-\frac{12}{30}=\frac{5-12}{30}=\frac{-7}{30}=-\frac{7}{30}</math>
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Version vom 07:34, 19. Sep. 2008

We multiply the top and bottom of each fraction by the other fraction's denominator so that they have a common denominator,

Vorlage:Displayed math

Then the numerators can be subtracted

Vorlage:Displayed math

Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_1.2:1c“