1.2 Übungen
Aus Online Mathematik Brückenkurs 1
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Version vom 09:02, 22. Okt. 2008
Exercise 1.2:1
Write as one fraction
| a) | \displaystyle \displaystyle \frac{7}{4}+\frac{11}{7} | b) | \displaystyle \displaystyle \frac{2}{7}-\frac{1}{5} | c) | \displaystyle \displaystyle \frac{1}{6}-\frac{2}{5} |
| d) | \displaystyle \displaystyle \frac{1}{3}+\frac{1}{4}+\frac{1}{5} | e) | \displaystyle \displaystyle \frac{8}{7}+\frac{3}{4}-\frac{4}{3} |
Answer
Laden...
Solution a
Solution b
Solution c
Solution d
Solution e
Exercise 1.2:2
Determine the lowest common denominator of
| a) | \displaystyle \displaystyle \frac{1}{6}+\frac{1}{10} | b) | \displaystyle \displaystyle \frac{1}{4}-\frac{1}{8} |
| c) | \displaystyle \displaystyle \frac{1}{12}-\frac{1}{14} | d) | \displaystyle \displaystyle \frac{2}{45}+\frac{1}{75} |
Answer
Solution a
Solution b
Solution c
Solution d
Exercise 1.2:3
Calculate the following by using the lowest common denominator.
| a) | \displaystyle \displaystyle\frac{3}{20}+\frac{7}{50}-\frac{1}{10} | b) | \displaystyle \displaystyle\frac{1}{24}+\frac{1}{40}-\frac{1}{16} |
Exercise 1.2:4
Simplify the following by writing each part as one fraction. The fraction should be in simplest possible form.
| a) | \displaystyle \displaystyle\frac{\displaystyle\frac{3}{5}}{\displaystyle\frac{7}{10}} | b) | \displaystyle \displaystyle\frac{\displaystyle\frac{2}{7}}{\displaystyle\frac{3}{8}} | c) | \displaystyle \displaystyle\frac{\displaystyle\frac{1}{4}-\frac{1}{5}}{\displaystyle\frac{3}{10}} |
Answer
Solution a
Solution b
Solution c
Exercise 1.2:5
Simplify the following by writing each part as one fraction. The fraction should be in simplest possible form.
| a) | \displaystyle \displaystyle \frac{2}{\displaystyle \frac{1}{7}\displaystyle -\frac{1}{15}} | b) | \displaystyle \displaystyle\frac{\displaystyle\frac{1}{2}\displaystyle+\frac{1}{3}}{\displaystyle\frac{1}{3}\displaystyle-\frac{1}{2}} | c) | \displaystyle \displaystyle\frac{\displaystyle\frac{3}{10}\displaystyle-\frac{1}{5}}{\displaystyle\frac{7}{8}\displaystyle-\frac{3}{16}} |
Answer
Solution a
Solution b
Solution c
Exercise 1.2:6
Simplify \displaystyle \ \,\displaystyle \frac{\displaystyle \frac{2}{\displaystyle 3+\frac{1}{2}}\displaystyle + \frac{\displaystyle \frac{1}{2}}{\displaystyle \frac{1}{4}\displaystyle -\frac{1}{3}}}{\displaystyle \frac{1}{2}\displaystyle - \frac{3}{\displaystyle 2-\frac{2}{7}}}
Answer
Solution
