Lösung 4.4:1a
Aus Online Mathematik Brückenkurs 1
(Unterschied zwischen Versionen)
K (Lösning 4.4:1a moved to Solution 4.4:1a: Robot: moved page) |
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- | {{ | + | In the unit circle's first quadrant, there is one angle whose sine value equals |
- | + | <math>\frac{1}{2}</math> | |
- | {{ | + | and that is |
+ | <math>v={\pi }/{6}\;</math>. | ||
[[Image:4_4_1_a.gif|center]] | [[Image:4_4_1_a.gif|center]] | ||
+ | |||
+ | From the figures, we see that there is a further angle with the same sine value and it lies in the second quadrant. Because of symmetry, it makes the same angle with the negative | ||
+ | <math>x</math> | ||
+ | -axis as | ||
+ | <math>v={\pi }/{6}\;</math> | ||
+ | makes with the positive | ||
+ | <math>x</math> | ||
+ | -axis, i.e. the other angle is | ||
+ | <math>v=\pi -{\pi }/{6}\;={5\pi }/{6}\;</math> |
Version vom 11:58, 30. Sep. 2008
In the unit circle's first quadrant, there is one angle whose sine value equals \displaystyle \frac{1}{2} and that is \displaystyle v={\pi }/{6}\;.
From the figures, we see that there is a further angle with the same sine value and it lies in the second quadrant. Because of symmetry, it makes the same angle with the negative \displaystyle x -axis as \displaystyle v={\pi }/{6}\; makes with the positive \displaystyle x -axis, i.e. the other angle is \displaystyle v=\pi -{\pi }/{6}\;={5\pi }/{6}\;