Lösung 3.3:5c

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Because
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<center> [[Image:3_3_5c.gif]] </center>
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<math>\text{ln 1}=0</math>
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(a consequence of
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<math>e^{0}=1</math>
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),
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<math>\left( \text{ln 1} \right)\centerdot e^{2}=0\centerdot e^{2}=0</math>

Version vom 08:29, 26. Sep. 2008

Because \displaystyle \text{ln 1}=0 (a consequence of \displaystyle e^{0}=1 ),


\displaystyle \left( \text{ln 1} \right)\centerdot e^{2}=0\centerdot e^{2}=0

Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_3.3:5c“