Lösung 2.1:3a
Aus Online Mathematik Brückenkurs 1
(Unterschied zwischen Versionen)
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| - | + | If we look at the expression, we see that it can be written as <math>x^2-6^2</math> and can therefore be factorized using the conjugate rule | |
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| - | If we look at the expression, we see that it can be written as <math>x^2-6^2</math> and can therefore be factorized using the conjugate rule | + | |
| - | + | {{Displayed math||<math> x^2-36=x^2-6^2=(x+6)(x-6)\,\textrm{.}</math>}} | |
Because the factors <math> x+6 </math> and <math> x-6 </math> are linear expressions, they cannot be factorized any further (as polynomial factors). | Because the factors <math> x+6 </math> and <math> x-6 </math> are linear expressions, they cannot be factorized any further (as polynomial factors). | ||
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Version vom 08:26, 23. Sep. 2008
If we look at the expression, we see that it can be written as \displaystyle x^2-6^2 and can therefore be factorized using the conjugate rule
Because the factors \displaystyle x+6 and \displaystyle x-6 are linear expressions, they cannot be factorized any further (as polynomial factors).
