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Lösung 1.3:3b

Aus Online Mathematik Brückenkurs 1

(Unterschied zwischen Versionen)
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K (Lösning 1.3:3b moved to Solution 1.3:3b: Robot: moved page)
Zeile 1: Zeile 1:
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{{NAVCONTENT_START}}
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If we divide
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<center> [[Image:1_3_3b.gif]] </center>
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<math>243</math>
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{{NAVCONTENT_STOP}}
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successively by
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<math>3</math>, we see that
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<math>\begin{align}
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& 243=3\centerdot 81=3\centerdot 3\centerdot 27=3\centerdot 3\centerdot 3\centerdot 9 \\
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& \\
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& =3\centerdot 3\centerdot 3\centerdot 3\centerdot 3=3^{5} \\
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\end{align}</math>

Version vom 11:34, 15. Sep. 2008

If we divide 243 successively by 3, we see that


243=381=3327=3339=33333=35

Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_1.3:3b“