Lösung 1.1:7c

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K (Lösning 1.1:7c moved to Solution 1.1:7c: Robot: moved page)
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Tittar vi närmare på talet så ser vi att sifferkombinationen 001 upprepas från och med den andra decimalen
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If we look more closely at this number, we see that the combination 001 is repeated from the second decimal place onwards,
<center><math>0{,}2\ \underline{001}\ \underline{001}\ \underline{001}\,\ldots</math></center>
<center><math>0{,}2\ \underline{001}\ \underline{001}\ \underline{001}\,\ldots</math></center>
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och det avslöjar att talet är rationellt.
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and this reveals that the number is rational.
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Genom att sedan multiplicera talet med 10 ett antal gånger kan vi skifta decimalkommat stegvis åt höger
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By multiplying a certain number of times by 10 we can move the decimal place step by step to the right.
::<math>\insteadof[right]{10000x}{x}{}=0\,,\,2\ 001\ 001\ 001\,\ldots</math>
::<math>\insteadof[right]{10000x}{x}{}=0\,,\,2\ 001\ 001\ 001\,\ldots</math>
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::<math>\insteadof[right]{10000x}{10000x}{}=2001\,,\,\underline{001}\ \underline{001}\ 1\ldots</math>
::<math>\insteadof[right]{10000x}{10000x}{}=2001\,,\,\underline{001}\ \underline{001}\ 1\ldots</math>
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I denna lista ser vi att talen 10''x'' och 10000''x'' har samma decimalutveckling, och det betyder att
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In this list, we see that 10''x'' and 10000''x'' have the same decimal expansion, which means that
::<math>10000x-10x = 2001{,}\underline{001}\ \underline{001}\ \underline{001}\,\ldots - 2{,}\underline{001}\ \underline{001}\ \underline{001}\,\ldots</math>
::<math>10000x-10x = 2001{,}\underline{001}\ \underline{001}\ \underline{001}\,\ldots - 2{,}\underline{001}\ \underline{001}\ \underline{001}\,\ldots</math>
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::<math>\phantom{10000x-10x}{} = 1999\,\mbox{.}\quad</math>(decimalerna tar ut varandra)
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::<math>\phantom{10000x-10x}{} = 1999\,\mbox{.}\quad</math>(decimal parts cancel)
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Eftersom <math>10000x-10x = 9990x</math> så är
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As <math>10000x-10x = 9990x</math> then
::<math>9990x = 1999\quad\Leftrightarrow\quad x = \frac{1999}{9990}\,\mbox{.}</math>
::<math>9990x = 1999\quad\Leftrightarrow\quad x = \frac{1999}{9990}\,\mbox{.}</math>
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Version vom 14:00, 14. Sep. 2008