Antwort 4.2:1
Aus Online Mathematik Brückenkurs 1
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Version vom 14:52, 8. Sep. 2008
| a) | \displaystyle x=13\cdot\tan {27 ^\circ} \approx 6\textrm{.}62 | b) | \displaystyle x=25\cdot\cos {32 ^\circ} \approx 21\textrm{.}2 |
| c) | \displaystyle x=\displaystyle\frac{14}{\tan {40 ^\circ}} \approx 16\textrm{.}7 | d) | \displaystyle x=\displaystyle\frac{16}{\cos {20 ^\circ}} \approx 17\textrm{.}0 |
| e) | \displaystyle x=\displaystyle\frac{11}{\sin {35 ^\circ}} \approx 19\textrm{.}2 | f) | \displaystyle x=\displaystyle\frac{19}{\tan {50 ^\circ}} \approx 15\textrm{.}9 |
