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Lösung 2.1:1f

Aus Online Mathematik Brückenkurs 1

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Zeile 5: Zeile 5:
&= 25+10\cdot 4y + 4^2y^2\\
&= 25+10\cdot 4y + 4^2y^2\\
&= 25+40y+16y^4\\
&= 25+40y+16y^4\\
-
&= 16y^2 +40y 25
+
&= 16y^2 +40y + 25
\end{align}
\end{align}
</math>
</math>

Version vom 09:19, 13. Aug. 2008

The squaring rule (a+b)2=a2+2ab+b2 with a=5 and b=4y gives

(5+4y)2=52+254y+(4y)2=25+104y+42y2=25+40y+16y4=16y2+40y+25

Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_2.1:1f“