Antwort 3.4:2
Aus Online Mathematik Brückenkurs 1
(Unterschied zwischen Versionen)
(Ny sida: {| width="100%" cellspacing="10px" |a) |width="33%" | <math> \left\{ \eqalign{ x_1&=\sqrt2 \cr x_2&=-\sqrt2 } \right. </math> |b) |width="33%" | <math>x=\ln \left(\displaystyle\frac{\sqrt1...) |
(Translated into English) |
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| Zeile 5: | Zeile 5: | ||
|width="33%" | <math>x=\ln \left(\displaystyle\frac{\sqrt17}{2}-\frac{1}{2}\right)</math> | |width="33%" | <math>x=\ln \left(\displaystyle\frac{\sqrt17}{2}-\frac{1}{2}\right)</math> | ||
|c) | |c) | ||
| - | |width="33%" | | + | |width="33%" | No solution |
|} | |} | ||
Version vom 10:42, 8. Sep. 2008
| a) | \displaystyle \left\{ \eqalign{ x_1&=\sqrt2 \cr x_2&=-\sqrt2 } \right. | b) | \displaystyle x=\ln \left(\displaystyle\frac{\sqrt17}{2}-\frac{1}{2}\right) | c) | No solution |
