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Antwort 4.2:1

Aus Online Mathematik Brückenkurs 1

(Unterschied zwischen Versionen)
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(Ny sida: {| width="100%" cellspacing="10px" |a) |width="50%" | <math>x=13\cdot\tan {27 ^\circ} \approx 6{,}62</math> |b) |width="50%" | <math>x=25\cdot\cos {32 ^\circ} \approx 21{,}2</math> |- |c) ...)
Aktuelle Version (17:44, 22. Okt. 2008) (bearbeiten) (rückgängig)
K (hat „Answer 4.2:1“ nach „Antwort 4.2:1“ verschoben: Robot: moved page)
 
(Der Versionsvergleich bezieht 2 dazwischen liegende Versionen mit ein.)
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{| width="100%" cellspacing="10px"
{| width="100%" cellspacing="10px"
|a)
|a)
-
|width="50%" | <math>x=13\cdot\tan {27 ^\circ} \approx 6{,}62</math>
+
|width="50%" | <math>x=13\cdot\tan {27 ^\circ} \approx 6\textrm{.}62</math>
|b)
|b)
-
|width="50%" | <math>x=25\cdot\cos {32 ^\circ} \approx 21{,}2</math>
+
|width="50%" | <math>x=25\cdot\cos {32 ^\circ} \approx 21\textrm{.}2</math>
|-
|-
|c)
|c)
-
|width="50%" | <math>x=\displaystyle\frac{14}{\tan {40 ^\circ}} \approx 16{,}7</math>
+
|width="50%" | <math>x=\displaystyle\frac{14}{\tan {40 ^\circ}} \approx 16\textrm{.}7</math>
|d)
|d)
-
|width="50%" | <math>x=\displaystyle\frac{16}{\cos {20 ^\circ}} \approx 17{,}0</math>
+
|width="50%" | <math>x=\displaystyle\frac{16}{\cos {20 ^\circ}} \approx 17\textrm{.}0</math>
|-
|-
|e)
|e)
-
|width="50%" | <math>x=\displaystyle\frac{11}{\sin {35 ^\circ}} \approx 19{,}2</math>
+
|width="50%" | <math>x=\displaystyle\frac{11}{\sin {35 ^\circ}} \approx 19\textrm{.}2</math>
|f)
|f)
-
|width="50%" | <math>x=\displaystyle\frac{19}{\tan {50 ^\circ}} \approx 15{,}9</math>
+
|width="50%" | <math>x=\displaystyle\frac{19}{\tan {50 ^\circ}} \approx 15\textrm{.}9</math>
|}
|}

Aktuelle Version

a) x=13tan276.62 b) x=25cos3221.2
c) x=14tan4016.7 d) x=16cos2017.0
e) x=11sin3519.2 f) x=19tan5015.9
Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/Antwort_4.2:1“