Antwort 4.3:6
Aus Online Mathematik Brückenkurs 1
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| {| width="100%" cellspacing="10px" | {| width="100%" cellspacing="10px" | ||
| |a) | |a) | ||
| - | |width="100%" |  <math>\sin{v}=-\displaystyle \frac{\sqrt{7}}{4}\quad</math>  | + | |width="100%" |  <math>\sin{v}=-\displaystyle \frac{\sqrt{7}}{4}\quad</math> und <math>\quad\tan{v}=-\displaystyle \frac{\sqrt{7}}{3}\,</math>  | 
| |- | |- | ||
| |b) | |b) | ||
| - | |width="100%"  | <math>\cos{v}=-\displaystyle \frac{\sqrt{91}}{10}\quad</math>  | + | |width="100%"  | <math>\cos{v}=-\displaystyle \frac{\sqrt{91}}{10}\quad</math> und <math>\quad\tan{v}=-\displaystyle \frac{3}{\sqrt{91}}\,</math> | 
| |- | |- | ||
| |c) | |c) | ||
| - | |width="100%" | <math>\sin{v}=-\displaystyle \frac{3}{\sqrt{10}}\quad</math>  | + | |width="100%" | <math>\sin{v}=-\displaystyle \frac{3}{\sqrt{10}}\quad</math> und <math>\quad\cos{v}=-\displaystyle \frac{1}{\sqrt{10}}\,</math> | 
| |} | |} | ||
Aktuelle Version
| a) | \displaystyle \sin{v}=-\displaystyle \frac{\sqrt{7}}{4}\quad und \displaystyle \quad\tan{v}=-\displaystyle \frac{\sqrt{7}}{3}\, | 
| b) | \displaystyle \cos{v}=-\displaystyle \frac{\sqrt{91}}{10}\quad und \displaystyle \quad\tan{v}=-\displaystyle \frac{3}{\sqrt{91}}\, | 
| c) | \displaystyle \sin{v}=-\displaystyle \frac{3}{\sqrt{10}}\quad und \displaystyle \quad\cos{v}=-\displaystyle \frac{1}{\sqrt{10}}\, | 
 
		  