Antwort 4.4:7
Aus Online Mathematik Brückenkurs 1
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Aktuelle Version
| a) | \displaystyle \left\{ \matrix{
x=\displaystyle \frac{\pi}{6}+2n\pi\cr x=\displaystyle \frac{5\pi}{6}+2n\pi\cr x=\displaystyle \frac{3\pi}{2}+2n\pi }\right. | b) | \displaystyle x=\pm \displaystyle \frac{\pi}{3} + 2n\pi |
| c) | \displaystyle \left\{ \matrix{
x=\displaystyle \frac{\pi}{2}+2n\pi\cr x=\displaystyle \frac{\pi}{14}+\displaystyle \frac{2n\pi}{7} }\right. |
