Antwort 2.1:3
Aus Online Mathematik Brückenkurs 1
(Unterschied zwischen Versionen)
(Ny sida: {| width="100%" cellspacing="10px" |a) |width="33%" | <(x+6)(x-6)</math> |b) |width="33%" | <math>5(x+2)(x-2)</math> |c) |width="33%" | <math>$(x+3)^2</math> |- |d) || <math>(x-5)^2</math>...) |
K (hat „Answer 2.1:3“ nach „Antwort 2.1:3“ verschoben: Robot: moved page) |
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| (Der Versionsvergleich bezieht 2 dazwischen liegende Versionen mit ein.) | |||
| Zeile 1: | Zeile 1: | ||
{| width="100%" cellspacing="10px" | {| width="100%" cellspacing="10px" | ||
|a) | |a) | ||
| - | |width="33%" | <(x+6)(x-6)</math> | + | |width="33%" | <math>(x+6)(x-6)</math> |
|b) | |b) | ||
|width="33%" | <math>5(x+2)(x-2)</math> | |width="33%" | <math>5(x+2)(x-2)</math> | ||
|c) | |c) | ||
| - | |width="33%" | <math> | + | |width="33%" | <math>(x+3)^2</math> |
|- | |- | ||
|d) | |d) | ||
Aktuelle Version
| a) | \displaystyle (x+6)(x-6) | b) | \displaystyle 5(x+2)(x-2) | c) | \displaystyle (x+3)^2 |
| d) | \displaystyle (x-5)^2 | e) | \displaystyle -2x(x+3)(x-3) | f) | \displaystyle (4x+1)^2 |
