Lösung 4.1:3c
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Version vom 14:45, 22. Okt. 2008
In this right-angled triangle, the side of length 17 is the hypotenuse (it is the side which is opposite the right angle). The Pythagorean theorem then gives
| \displaystyle 17^2 = 8^2 + x^2 |
or
| \displaystyle x^2 = 17^2 - 8^2\,\textrm{.} |
We get
| \displaystyle \begin{align}
x &= \sqrt{17^2-8^2} = \sqrt{289-64} = \sqrt{225}\\[5pt] &= \sqrt{9\cdot 25} = \sqrt{3^2\cdot 5^2} = 3\cdot 5 = 15\,\textrm{.} \end{align} |
