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Lösung 3.4:1c

(Unterschied zwischen Versionen)

Version vom 14:41, 22. Okt. 2008

The equation has the same form as the equation in exercise b and we can therefore use the same strategy.

First, we take logs of both sides,

3ex

=ln

and use the log laws to make x more accessible,

ln3+x

lne=ln7+x

ln2.

Then, collect together the x terms on the left-hand side,

x(lne−ln2)=ln7−ln3.

The solution is now

x=lne−ln2ln7−ln3=1−ln2ln7−ln3.