Lösung 3.3:3b
Aus Online Mathematik Brückenkurs 1
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Version vom 14:34, 22. Okt. 2008
Because we are working with \displaystyle \log _{9}, we express 1/3 as a power of 9,
| \displaystyle \frac{1}{3} = \frac{1}{\sqrt{9}} = \frac{1}{9^{1/2}} = 9^{-1/2}\,\textrm{.} |
Using the logarithm laws, we get
| \displaystyle \log_9\frac{1}{3} = \log_9 9^{-1/2} = -\frac{1}{2}\cdot\log_9 9 = -\frac{1}{2}\cdot 1 = -\frac{1}{2}\,\textrm{.} |
