Lösung 2.3:8c
Aus Online Mathematik Brückenkurs 1
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Version vom 14:15, 22. Okt. 2008
By completing the square, we can rewrite the function as
| \displaystyle f(x) = x^{2}-6x+11 = (x-3)^{2} - 3^{2} + 11 = (x-3)^{2} + 2, |
and when the function is written in this way, we see that the graph \displaystyle y = (x-3)^{2} + 2 is the same curve as the parabola \displaystyle y=x^{2}, but shifted two units up and three units to the right (see sub-exercise a and b).
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| The graph of f(x) = x² | The graph of f(x) = x² - 6x + 11 |
