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Lösung 2.3:8c

Aus Online Mathematik Brückenkurs 1

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Version vom 14:15, 22. Okt. 2008

By completing the square, we can rewrite the function as

f(x)=x2−6x+11=(x−3)2−32+11=(x−3)2+2

and when the function is written in this way, we see that the graph y=(x−3)2+2 is the same curve as the parabola y=x2, but shifted two units up and three units to the right (see sub-exercise a and b).


 
The graph of f(x) = x² The graph of f(x) = x² - 6x + 11
Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_2.3:8c“