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Lösung 2.2:1d

Aus Online Mathematik Brückenkurs 1

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Version vom 13:53, 22. Okt. 2008

Move x to the left-hand side by subtracting 2x from both sides,

5x+7−2x=2x−6−2x

which gives

3x+7=−6.

Subtract 7 from both sides,

3x+7−7=−6−7

so that the term 3x alone remains on the left-hand side

3x=−13.

Then, divide both sides by 3,

33x=−313,

to get x,

x=−313.
Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_2.2:1d“